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Chemistry help
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02-15-2011, 09:54 PM | #1 |
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Chemistry help
I need to get these by midnight tonight but I have no idea how to do them.
Problem 1- Problem 2- Last edited by aretardedorange; 02-15-2011 at 10:59 PM.. |
02-15-2011, 10:17 PM | #3 |
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sounds like it. Just remember to do your phase changes. Thats a diff formula.
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02-15-2011, 10:17 PM | #4 |
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1) 63360 degrees C
2) 114153.62 degrees C I think that's right, last time i took chem was in hs lol
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02-15-2011, 10:18 PM | #5 |
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The answers would be in Joules.
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02-15-2011, 10:21 PM | #6 |
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02-15-2011, 10:23 PM | #7 | |
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i did end up being a biochemistry major and graduating with honors out of college though... but i still would have to do some mental digging to do those problems, even tho they look simple as pie |
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02-15-2011, 10:24 PM | #8 |
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Yes that formula. But I reboot my computer and it gave me new problems. If you could do these two it would be much appreciated.
Last edited by aretardedorange; 02-15-2011 at 10:59 PM.. |
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02-15-2011, 10:41 PM | #12 |
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1) 0.1222
2) 142718.4 the first one's tricky on the first one, since the metal is in solution, you'll end up having the same temperature (between water and the metal) which means T-final for the water is also 61.1, so you throw that into the Q = mc(Tf-Ti) equation and you get the energy change by the water, Q = 329.28 since you have Q, which will fit into the Q=mcT on the metal equation, you can put everything in and find c 329.28 = (55.89)(c)(61.1 - 12.9) rearrange the equation and solve for c
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02-15-2011, 10:47 PM | #13 |
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02-15-2011, 10:49 PM | #15 | |
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02-15-2011, 10:49 PM | #16 |
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yeah it is i didn't put the negative cause the question was worded funny 'how much is removed' but yeah it's technically negative
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02-15-2011, 10:51 PM | #17 |
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awww i'm sorry i was trying to do it as quickly as i could and couldn't really look it through
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02-15-2011, 10:51 PM | #18 |
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02-15-2011, 10:53 PM | #19 | |
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Thanks everyone that helped! Once again much appreciated! |
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02-15-2011, 11:04 PM | #20 | |
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C=Q/M(deltaT) First I tried to solve for TF for the 2nd part. (78.7g)(4.184)(Tf-66.2) =85J (55.89)(C)(61.1-12.9) C=2693.9 85J/2693.9 .0316J/G [C] |
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02-15-2011, 11:09 PM | #21 | |
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booo it bugs me when i get something wrong!!!!
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